In the pure non-competitive model, where can the inhibitor bind?
At fixed enzyme and inhibitor concentrations, what does reversible competitive inhibition do to Vmax and apparent Km?
Finding that an inhibitor binds away from the active site is enough to prove pure non-competitive inhibition.
Circle one: True False
An inhibitor binds only to the enzyme-substrate complex. Vmax and apparent Km both decrease by the same factor. Which inhibition type fits?
Under otherwise identical conditions, an inhibitor leaves Vmax at 24 rate units but moves the substrate concentration giving 12 rate units from 2 to 6 mmol/L. Which model fits?
As substrate concentration rises at fixed inhibitor concentration, why can competitive inhibition be overcome but pure non-competitive inhibition cannot?
ATP availability rises while other conditions stay suitable. What feedback response can occur in cellular respiration?
A pathway's final product slows an earlier purified enzyme. Removing the product restores activity without replacing the enzyme. Substrate concentration, temperature and pH are unchanged. Which explanation best fits?