For the perpendicular rod-and-rails arrangement, both the magnetic-force calculation and the changing-loop-flux calculation give emf magnitude B l v.
Circle one: True False
A rod of length l moves at speed v perpendicular to uniform B. The rod lies along v cross B. What is its emf magnitude?
Why can electric-field circulation exist around a time-varying magnetic field even when no wire is present?
In the perpendicular rod-and-rails arrangement, speed doubles while B and rod length stay fixed. What happens to the emf magnitude?
A 2.0 m rod moves at 3.0 m/s perpendicular to a uniform 0.5 T field. The rod lies along v cross B. Give its emf magnitude in volts.
Answer: ______________
A copper sheet slows as it enters and leaves a magnetic-field region. Where does the mechanical energy removed by eddy-current braking go?
A perpendicular rod-and-rails circuit has B = 2 T, l = 1 m and v = 3 m/s. Total resistance is 2 ohms, inductance is negligible and there is no other source. Give the current magnitude in A.
Answer: ______________
A fixed closed path encloses two regions. With one consistent surface orientation, their flux-change rates are +0.018 Wb/s and -0.006 Wb/s. The electric-field circulation around the matching path direction is -0.024 V.
Circle one: True False