Which condition defines a candidate key under the given functional dependencies?
The rule student ID -> email holds in every allowed state. What does it require?
A relation is in BCNF exactly when every nontrivial functional dependency has a superkey on its left.
Circle one: True False
R(A,B,C) has only the given rules A -> B and B -> A, plus their consequences. Which list contains all candidate keys?
R has attributes A, B and C. Using the rules A -> B and B -> C, what is {A}+?
R has A, B, C and D. Its only given rules are A,B -> C and C -> D. How many attributes are in {A}+?
Answer: ______________
R(ID,email,dorm) has only ID -> email and email -> dorm, plus their consequences. Which split on email -> dorm retains every attribute and is lossless?
R(ID,email,dorm) has only ID -> email and email -> dorm, plus their consequences. Pat says it is in BCNF because email is unique today. Why does that not establish BCNF?