Phase Portraits, Equilibria and Stability · seed 1 · A4, ink-friendly. The answer key prints on its own page for grown-ups.
به انگلیسی

Reading motion in the plane

Mathematics · Differential Equations · ages 21-22
Name ______________________   Date ____________

  1. The linear system x' = Ax has A = [[0, 1], [-4, 0]]. What type of equilibrium is the origin?

    • Saddle
    • Stable node
    • Unstable spiral
    • Centre

  2. A linear system has eigenvalues minus 4 and 1 at the origin. What type of equilibrium is it?

    • Unstable node
    • Saddle
    • Stable spiral

  3. An equilibrium of a planar system is a point where both rates of change are zero.

    Circle one:   True   False

  4. A linear system has eigenvalues 2 and 6 at the origin. What type is it?

    • Unstable node
    • Saddle
    • Unstable spiral

  5. A phase portrait shows closed loops around the origin. Every nearby trajectory stays nearby but never settles into the point. Is the origin a centre?

    Circle one:   True   False

  6. A linear system has eigenvalues -2 + i and -2 - i at the origin. What type of equilibrium is it?

    • Unstable spiral
    • Centre
    • Stable spiral
    • Saddle

  7. After linearising a predator prey model at an equilibrium you get a centre. What should you conclude?

    • The nonlinear portrait is certainly a centre
    • It may be a slow spiral in the full model
    • The equilibrium must really be a saddle

  8. A linear system has eigenvalues minus 3 plus 4i and minus 3 minus 4i. What is the real part?

    Answer: ______________

  9. A student sees eigenvalues 2i and minus 2i and reports an unstable spiral. What is wrong?

    • A pure imaginary pair gives a stable node
    • Nothing is wrong with that report
    • A pure imaginary pair gives a centre

  10. Linearisation of a nonlinear system at an equilibrium gives purely imaginary eigenvalues. Ana concludes the nonlinear system must show closed loops there. Is Ana right?

    Circle one:   True   False

LightMySky · lightmysky.comW1-mt_ULuZk4lmGr-s1

Answer key

For grown-ups. Fold this page away before handing over the rest.

Reading motion in the plane W1-mt_ULuZk4lmGr-s1

  1. Centre · The characteristic equation λ² + 4 = 0 gives λ = ±2i, a pure imaginary pair: a centre.
  2. Saddle · The eigenvalues are real with opposite signs, so the origin is a saddle.
  3. True · That is the definition you learned: both rates vanish so the state can rest.
  4. Unstable node · Both eigenvalues are real and positive, so every nearby trajectory moves away without rotating: an unstable node.
  5. True · Closed loops that stay nearby mean stability, but since paths never settle into the point, it is not asymptotically stable. That is exactly a centre.
  6. Stable spiral · A complex pair with negative real part -2: rotation with inward drift, a stable spiral.
  7. It may be a slow spiral in the full model · A centre sits on the borderline, where the dropped nonlinear terms can change the picture.
  8. -3 · The real part of -3 ± 4i is -3.
  9. A pure imaginary pair gives a centre · With zero real part there is rotation but no inward or outward drift, so the shape is a centre.
  10. False · Ana is wrong. A centre is a borderline case: tiny nonlinear terms can turn the loops into a slow inward or outward spiral, which the linear picture cannot show.
Worksheet · LightMySky