Lines and Planes in Space · بذر 1 · A۴، مناسب چاپ. پاسخ‌نامه در صفحه‌ای جدا برای بزرگ‌ترها چاپ می‌شود.
به انگلیسی

Points, directions, and normals in space

ریاضی · هندسه · سن ۱۹ تا ۲۰ سال
نام ______________________   تاریخ ____________
  1. The line r = (1, 0, 2) + t(3, -1, 2) passes through (1, 0, 2) when t = 0. What is its x-coordinate when t = 2?

    پاسخ: ______________

  2. Which vector is normal to the plane 2x - y + 4z = 7?

    • (2, -1, 4)
    • (2, 1, 4)
    • (7, -1, 4)
    • (2, -1, 7)
  3. Which vector is normal to the plane 2x minus y plus 4z = 7?

    • (2, 1, 4)
    • (2, negative 1, 4)
    • (7, negative 1, 4)
  4. What is the distance from the point (0, 0, 5) to the plane z = 2? Give a number.

    پاسخ: ______________

  5. What is the angle between the coordinate planes x = 0 and y = 0?

    • 45 degrees
    • 90 degrees
    • 0 degrees
    • 60 degrees
  6. A plane has normal vector (1, 2, negative 1) and passes through (3, 0, 1). Written as x plus 2y minus z = k, what is k? Give a number.

    پاسخ: ______________

  7. Line L1 passes through (0, 0, 0) with direction (1, 0, 0). Line L2 passes through (0, 1, 0) with direction (0, 0, 1). How are the lines related?

    • Parallel
    • Intersecting
    • Skew
  8. Line L1 passes through (0, 0, 0) with direction (1, 0, 0). Line L2 passes through (0, 1, 0) with direction (0, 0, 1). How are the lines related?

    • parallel
    • intersecting
    • skew
    • identical
  9. Two lines are skew. Which operation starts the distance calculation between them?

    • The cross product of the two direction vectors
    • The dot product of the two direction vectors
    • The sum of the two direction vectors
  10. A plane has normal vector (1, 2, -1) and passes through (3, 0, 1). Written in the form x + 2y - z = k, what is k?

    پاسخ: ______________

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Points, directions, and normals in space W1-mt_kIX5ak1GRv-s1

  1. 7 · x = 1 + 3t, so at t = 2 the x-coordinate is 1 + 6 = 7.
  2. (2, -1, 4) · The coefficients of x, y and z in the plane equation give a normal vector directly: (2, -1, 4).
  3. (2, negative 1, 4) · The coefficients of x, y and z in the plane equation give a normal vector directly.
  4. 3 · The plane z = 2 is horizontal, so the distance is the vertical gap: 5 minus 2.
  5. 90 degrees · The normals (1, 0, 0) and (0, 1, 0) have dot product 0, so the planes are perpendicular: 90 degrees.
  6. 2 · Substitute the point: 3 plus 2 times 0 minus 1 is 2, so k is 2.
  7. Skew · The directions are not multiples, so the lines are not parallel, yet L1 has y = 0 while L2 has y = 1, so they never meet.
  8. skew · The directions are not multiples, so the lines are not parallel. L1 has y = 0, z = 0 while L2 has y = 1, so they never meet. Nonparallel lines that never meet are skew.
  9. The cross product of the two direction vectors · The common perpendicular comes from the cross product, and its length over the direction lengths gives the gap.
  10. 2 · Substitute the point: 3 + 2 x 0 - 1 = 2, so k = 2.
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