Sampling Distributions and the Central Limit Theorem · seed 1 · A4, ink-friendly. The answer key prints on its own page for grown-ups.
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Crowds behave better than individuals

Mathematics · Data & Statistics · ages 17-18
Name ______________________   Date ____________
  1. Independent observations come from a population with standard deviation 12. For samples of size 36, what is the standard error of the mean?

    Answer: ______________

  2. Each sample contains 4 independent observations from the same population with finite positive standard deviation. What is the ratio of the sample mean's standard error to that population standard deviation? Give a decimal.

    Answer: ______________

  3. Two populations have standard deviations 18 and 24. Each sample contains 36 independent observations from its population. Which population gives the larger standard error of the sample mean?

    • The population with σ = 18
    • The population with σ = 24
    • Both give the same spread
    • Their means decide the spread
  4. For independent random observations from the same population with finite, positive variance, what happens to the standard error of the mean as sample size grows?

    • The standard error decreases
    • The standard error increases
    • The standard error is unchanged
  5. Take 16 independent observations from a normal population with mean 65 and standard deviation 16. A left-cumulative table gives Φ(1) = 0.8413. Using that entry, find the probability that the sample mean exceeds 69.

    Answer: ______________

  6. Independent observations come from one population with finite mean and finite positive variance. When n is large enough for the central limit theorem approximation, what shape does the distribution of sample means have?

    • Uniform over a fixed interval
    • Strongly skewed in every case
    • Approximately normal
  7. Independent observations come from a normal population. What can be said about the sample mean for samples of size 4?

    • It is normal only when n reaches 30
    • It must have the population's spread
    • It is exactly normally distributed
    • It must be uniform rather than normal
  8. Dan takes 64 independent observations from a population with standard deviation 24. He reports 24 / 64 = 0.375 as the standard error. What is the correct standard error divided by his reported value?

    Answer: ______________

  9. For independent observations from a population with standard deviation 20, samples of 25 have standard error 4. What standard error do samples of 100 have?

    Answer: ______________

  10. For independent random observations from one population with finite mean and variance, increasing sample size moves the expected sample mean towards the population mean.

    Circle one:   True   False

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Answer key

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Crowds behave better than individuals W1-mt_nugaEeUSii-s1

  1. 2 · Standard error = 12 / √36 = 12 / 6 = 2.
  2. 0.5 · The ratio is 1 / √n. With n = 4, it is 1 / 2 = 0.5.
  3. The population with σ = 24 · Both denominators are √36 = 6. The standard errors are 18 / 6 = 3 and 24 / 6 = 4, so the population with σ = 24 gives the larger one.
  4. The standard error decreases · The standard error is σ / √n. The population's σ stays fixed while √n grows, so the quotient decreases.
  5. 0.1587 · The standard error is 16 / √16 = 4. The boundary has z = (69 - 65) / 4 = 1. The upper-tail probability is approximately 1 - 0.8413 = 0.1587.
  6. Approximately normal · The central limit theorem supports an approximately normal sampling distribution for sufficiently large n under the stated assumptions.
  7. It is exactly normally distributed · Independent observations from a normal population have an exactly normal sample mean for every positive n. Its standard error is σ / √4 = σ / 2.
  8. 8 · Dan divides by n instead of √n. The correct standard error is 24 / √64 = 24 / 8 = 3. Dividing it by his reported value gives 3 / 0.375 = 8.
  9. 2 · Standard error = 20 / √100 = 20 / 10 = 2. Multiplying sample size by four halves the standard error.
  10. False · The expected sample mean already equals μ for every sample size under these assumptions. Increasing n reduces its standard error rather than moving its centre.
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