Time Dilation and Length Contraction · seed 1 · A4, ink-friendly. The answer key prints on its own page for grown-ups.
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Measuring moving clocks and lengths

Science · Quantum & Modern Physics · ages 18-19
Name ______________________   Date ____________
  1. What is γ when relative speed v is zero?

    • 1
    • 0
    • Infinite
  2. A ship's light-clock mirrors are separated perpendicular to its constant motion. Why does the ground measure a longer tick time than the ship clock?

    • The light path is shorter; light speed remains c.
    • The light path is longer; light speed remains c.
    • The path is unchanged; light speed exceeds c.
  3. After correcting signal-travel delays, each of two inertial frames measures clocks at rest in the other frame as running faster.

    Circle one:   True   False

  4. One ship clock records 10 s between two ticks. The ship moves at constant speed relative to the ground with γ=2. After correcting signal-travel delays, what ground-frame time elapses between those same ticks, in seconds?

    Answer: ______________

  5. A rod's rest-frame length is 24 m. It moves along its length with γ=2 relative to the ground. Which ground measurement is valid?

    • 48 m, using both endpoint positions at one ground time.
    • 12 m, using endpoint positions at two different ground times.
    • 12 m, using both endpoint positions at one ground time.
  6. Why does time dilation increase the predicted fraction of fast muons reaching the ground, compared with treating their rest half-life as their ground-frame half-life?

    • The ground half-life grows by γ, so fewer half-lives pass.
    • The muons' rest half-life grows by γ during the flight.
    • The ground flight time grows by γ at fixed distance and speed.
  7. For a transverse light clock, (cΔt/2)^2=D^2+(vΔt/2)^2. Here D is mirror gap, Δt is ground tick time and Δτ is ship tick time. A student substitutes D=cΔt/2. Which correction is needed?

    • D=vΔt/2, since ship displacement sets the mirror gap.
    • D=cγΔt/2, since transverse lengths grow by γ.
    • D=cΔτ/2, since the ship tick covers distance 2D.
  8. Muons travel straight down from a production level to the ground at constant speed. The vertical gap H is fixed in ground coordinates. Ground flight time is 6 μs, γ=2 and rest half-life is 1.5 μs. Ignore energy loss. Which row gives consistent ground and muon-frame results?

    • Ground half-life 3 μs; muon gap H; muon flight 3 μs; survival 1/4.
    • Ground half-life 3 μs; muon gap H/2; muon flight 3 μs; survival 1/4.
    • Ground half-life 3 μs; muon gap H/2; muon flight 6 μs; survival 1/4.
    • Ground half-life 3 μs; muon gap H/2; muon flight 3 μs; survival 1/2.
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Answer key

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Measuring moving clocks and lengths W1-mt_7tpKiFWeG0-s1

  1. 1 · Substitute v=0 into γ=1/√(1−v²/c²). The result is 1/√1=1.
  2. The light path is longer; light speed remains c. · The ground-frame light path between moving mirrors is longer. At the same speed c, it takes longer.
  3. False · Each frame measures the other's moving clocks as slow. Signal arrival rates without delay correction are a different comparison.
  4. 20 · The ship clock records proper time Δτ=10 s. Ground time is Δt=γΔτ=2×10=20 s.
  5. 12 m, using both endpoint positions at one ground time. · The rest-frame measurement is proper length L0=24 m. Ground length is L0/γ=12 m, measured using simultaneous ground-frame endpoint positions.
  6. The ground half-life grows by γ, so fewer half-lives pass. · A longer ground-frame half-life means fewer half-lives pass during the same ground travel time, so a larger fraction survives.
  7. D=cΔτ/2, since the ship tick covers distance 2D. · In the ship frame, light travels round-trip distance 2D in proper time Δτ, so 2D=cΔτ and D=cΔτ/2.
  8. Ground half-life 3 μs; muon gap H/2; muon flight 3 μs; survival 1/4. · Ground half-life is 2×1.5=3 μs. Motion along H contracts the gap to H/2, giving muon-frame flight time 6÷2=3 μs. Both frames count two half-lives, so the expected surviving fraction is 1/4.
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