For y'=x-y, the field is horizontal at (2,2). Does this make y=2 a constant solution on an interval around x=2?
An Euler table for y'=x-y starts at (x0,y0)=(1,3) with h=0.25. What is x1?
Answer: ______________
For y'=x+2 and y(0)=1, one Euler step with h=1 gives 3. The exact value at x=1 is 3.5. How does the approximation compare?
For y prime = y minus x, what does the field segment at (2, 2) look like?
For a smooth problem, assume Euler's nonzero leading global error dominates at a sufficiently small step size. What usually happens to endpoint error when h is halved over the same interval?
You sketch the solution of y prime = x minus y through (0, 1). How does it leave the point?
When the exact solution's slope changes within an Euler step, why can the approximation drift from the solution?
For y'=x+1 with h=1, an Euler table has reached (x1,y1)=(1,1). What is the next approximation y2?
Answer: ______________
Kim starts at (0,0) for y'=x+1 with h=1. Kim uses the slope at x=1 and calculates y1=2. Which change gives an explicit Euler step?
Euler's method follows the exact solution for every differential equation and every step size.
Circle one: True False