The Biot-Savart Law and the Field of a Current Element · seed 1 · A4, ink-friendly. The answer key prints on its own page for grown-ups.
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Adding up magnetism piece by piece

Science · Electricity & Magnetism · ages 19-20
Name ______________________   Date ____________
  1. A current element dl points up the page. The unit vector rhat from that element to the field point points right. Which way does its Biot-Savart contribution point?

    • Into the page, perpendicular to both vectors
    • Out of the page, perpendicular to both vectors
    • Up the page, parallel to the current element
  2. One current element makes a nonzero field contribution. Hold its current, length and angle to the field-point direction fixed, excluding parallel and antiparallel orientations. How does the contribution's magnitude depend on distance r?

    • It grows in proportion to the square of distance
    • It falls in proportion to one over distance alone
    • It falls in proportion to one over distance squared
  3. At a fixed point away from an infinitely long straight wire, all its current elements contribute magnetic field in the same direction.

    Circle one:   True   False

  4. A circular wire loop of radius R carries steady current I in vacuum. Which expression gives its field magnitude at axial distance x from its centre?

    • mu0 I R^2/[2(R^2+x^2)^(3/2)]
    • mu0 I R^2/[2(R^2+x^2)^(1/2)]
    • mu0 I R^2/[2(R^2+x^2)^(5/2)]
  5. An infinitely long straight wire carries unchanged nonzero steady current. At four times the original perpendicular distance, what fraction of the original field magnitude remains? Give a decimal.

    Answer: ______________

  6. Two long, thin, parallel wires in vacuum carry nonzero steady currents in opposite directions. What magnetic interaction occurs?

    • They attract and pull toward one another
    • They repel and push away from one another
    • Their magnetic forces cancel on each wire
  7. For two long parallel wires, both current magnitudes double and their separation doubles. Their current directions stay unchanged. By what factor does magnetic force magnitude per unit length change?

    Answer: ______________

  8. A semicircular wire arc of radius R carries steady current I in vacuum. What field magnitude does this arc alone produce at its centre, excluding every other circuit part?

    • mu0 I/R
    • mu0 I/(2R)
    • mu0 I/(4R)
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Answer key

For grown-ups. Fold this page away before handing over the rest.

Adding up magnetism piece by piece W1-mt_RRsHUaXrFq-s1

  1. Into the page, perpendicular to both vectors · The ordered cross product is dl cross rhat. Up cross right points into the page.
  2. It falls in proportion to one over distance squared · The fixed, nonzero numerator gives dB proportional to 1/r^2. Parallel and antiparallel orientations are excluded because they would give zero contribution.
  3. True · For this straight wire, every dl cross rhat points the same way at the fixed point. The magnitudes can therefore be added in one scalar integral.
  4. mu0 I R^2/[2(R^2+x^2)^(3/2)] · Opposite elements cancel transverse components. Integrating the axial components gives mu0 I R^2/[2(R^2+x^2)^(3/2)].
  5. 0.25 · The integrated wire field follows 1/r. Multiplying perpendicular distance by four divides field magnitude by four, leaving 0.25 of the original.
  6. They repel and push away from one another · Opposite-direction parallel currents repel. Each wire experiences the magnetic field produced by the other.
  7. 2 · F/L follows I1 I2/r. The change factor is (2 times 2)/2 = 2.
  8. mu0 I/(4R) · A semicircle has angle pi radians. Substituting into mu0 I theta/(4 pi R) gives mu0 I/(4R).
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