Green's Theorem in the Plane · seed 1 · A4, ink-friendly. The answer key prints on its own page for grown-ups.
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Trading a rim walk for the inside

Mathematics · Calculus & Analysis · ages 20-21
Name ______________________   Date ____________
  1. Two adjacent regions share one edge. Their union has no hole. Their positively oriented boundary circulations for the same smooth field are 4 and -1. What is the positive circulation around the union's exterior boundary?

    Answer: ______________

  2. P and Q have continuous first partial derivatives near an annulus and both boundary circles. I_outer and I_inner are both circle integrals taken counterclockwise. Which expression equals the double integral of Q_x - P_y over the annulus?

    • I_outer + I_inner, using both given directions
    • I_inner - I_outer, reversing only the outer curve
    • I_outer - I_inner, reversing only the inner curve
    • I_outer alone, omitting the excluded hole's boundary
  3. Under Green's hypotheses, what equals ∮C(P dx + Q dy) when C is the positively oriented complete boundary of D?

    • Double integral of Q_x - P_y over D
    • Double integral of P_x + Q_y over D
    • Double integral of Q_y - P_x over D
  4. Green's theorem can be applied directly to any open arc without adding another curve to close the boundary.

    Circle one:   True   False

  5. Under Green's hypotheses, which choice makes ∮C(P dx + Q dy) equal the area of D when C is its positively oriented complete boundary?

    • P = x/2 and Q = y/2, giving Q_x - P_y = 0
    • P = y/2 and Q = -x/2, giving Q_x - P_y = -1
    • P = -y/2 and Q = x/2, giving Q_x - P_y = 1
  6. Around a simple closed curve traversed once clockwise, ∮(x dy - y dx) = -14. What is the enclosed area?

    Answer: ______________

  7. For F = (-y, 2x), the circulation around a positively oriented simple closed boundary is 27. Green's hypotheses hold. What is the enclosed area?

    Answer: ______________

  8. A field's circulation once counterclockwise around a simple closed curve is 5. What is its circulation once clockwise around the same curve?

    • 5: orientation does not change a line integral
    • 0: opposite orientations are added together
    • -5: reversing the path negates its integral
  9. A field is smooth near a simple closed curve but blows up at an enclosed point. A student applies Green's theorem to the entire filled region. Which check addresses the problem?

    • Use the theorem because all field values on the boundary are finite
    • Check the interior condition; the filled region contains a singularity
    • Check the boundary alone and omit the singular point without adding any boundary
  10. For F = (-y, x), C is the positively oriented complete boundary of a region D satisfying Green's hypotheses. What is Q_x - P_y, and how does circulation relate to area?

    • It is 2, so circulation is twice the area
    • It is 0, so circulation vanishes for every such region
    • It is -2, so circulation is minus twice the region's area
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Answer key

For grown-ups. Fold this page away before handing over the rest.

Trading a rim walk for the inside W1-mt_UDgivmPVEJ-s1

  1. 3 · The shared-edge integrals cancel. The exterior circulation is the sum 4 + (-1) = 3.
  2. I_outer - I_inner, reversing only the inner curve · Keep the outer circle counterclockwise and reverse the inner circle to clockwise. The complete-boundary integral is I_outer - I_inner.
  3. Double integral of Q_x - P_y over D · Green's circulation formula integrates Q_x - P_y over D. Both the derivative variables and subtraction order matter.
  4. False · The stated theorem requires a closed boundary. An open arc alone does not satisfy that condition.
  5. P = -y/2 and Q = x/2, giving Q_x - P_y = 1 · For P = -y/2 and Q = x/2, Q_x - P_y = 1/2 - (-1/2) = 1. Integrating 1 gives area.
  6. 7 · Reversing to counterclockwise gives integral 14. The area is half that value: 7.
  7. 9 · Q_x - P_y = 2 - (-1) = 3. Thus 27 = 3 × area, so the area is 9.
  8. -5: reversing the path negates its integral · The clockwise traversal reverses the path, so its circulation is -(5) = -5.
  9. Check the interior condition; the filled region contains a singularity · The included singular point violates the derivative condition for the filled region. Boundary smoothness alone is insufficient.
  10. It is 2, so circulation is twice the area · Q_x = 1 and P_y = -1, so Q_x - P_y = 2. Positive-boundary circulation is twice the area.
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