Separation of Variables and the Heat Equation · seed 1 · A4, ink-friendly. The answer key prints on its own page for grown-ups.
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Splitting the heat equation into space and time

Mathematics · Differential Equations · ages 22-23
Name ______________________   Date ____________
  1. A rod of length pi has both ends held at zero, with modes sin(nx) and eigenvalues L = n squared. Which n gives eigenvalue 16?

    Answer: ______________

  2. Separating u = X(x)T(t) in u_t = u_xx gives X''/X = T'/T. Why must both sides equal the same constant?

    • Because the equation is linear in u
    • A function of x alone equals a function of t alone
    • Because X and T must take equal values everywhere
    • Because both ends of the rod are held at zero
  3. For u_t equals 4 u_xx, separation u equals XT gives which pair of ordinary equations?

    • X double prime plus L X equals 0 with T prime plus 4 L T equals 0
    • X double prime plus 4 L X equals 0 with T prime plus 4 L T equals 0
    • X double prime minus L X equals 0 with T prime plus 4 L T equals 0
  4. For u_t equals u_xx, a separated product XT with X double prime plus L X equals 0 has time factor T equals e to the Lt.

    Circle one:   True   False

  5. On a rod of length pi with zero ends, the initial profile is f(x) = 7 sin 2x + sin 4x. What is b_2, the coefficient of sin 2x?

    Answer: ______________

  6. A rod with insulated ends has a mode with L = 0: a constant profile that never decays. Is that right?

    Circle one:   True   False

  7. A rod of length 4 has insulated ends, so the modes are cos(n pi x/4) with eigenvalues L = (n pi/4) squared. What is the smallest positive eigenvalue?

    • pi^2/16
    • pi^2/4
    • pi/4
    • pi^2/8
  8. The integral from 0 to pi of sin 2x times sin 5x equals 0 because distinct sine modes are orthogonal.

    Circle one:   True   False

  9. A rod of length 3 has both ends held at zero, so its modes are sin(n pi x over 3) with L equals (n pi over 3) squared. Each mode decays like e to the negative Lt. What is the slowest decay rate, to two decimal places?

    Answer: ______________

  10. For X'' + L X = 0 with X(0) = X(pi) = 0, which value of L gives only the zero solution?

    • L = 1
    • L = 4
    • L = 16
    • L = 5
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Answer key

For grown-ups. Fold this page away before handing over the rest.

Splitting the heat equation into space and time W1-mt_XnPDL0X1TL-s1

  1. 4 · L = n squared = 16 gives n = 4, the mode sin 4x.
  2. A function of x alone equals a function of t alone · The left side depends only on x and the right only on t. If they are equal for every x and t, neither can change, so both equal one constant.
  3. X double prime plus L X equals 0 with T prime plus 4 L T equals 0 · Dividing by 4XT gives X double prime over X equals T prime over 4T, shared as negative L, so the 4 sits on the time side only.
  4. False · The time equation is T prime plus L T equals 0, whose solution decays: T equals e to the negative Lt.
  5. 7 · Distinct sine modes are orthogonal, so the coefficient of sin 2x is read off: 7.
  6. True · Zero slope at both ends allows the constant function, with L = 0, and e^(0t) = 1 never decays.
  7. pi^2/16 · n = 0 gives L = 0; the smallest positive value is at n = 1: (pi/4)² = pi²/16.
  8. True · Distinct sine modes on the pi rod integrate to zero against each other.
  9. 1.1 · The smallest eigenvalue is n equals 1: (pi over 3) squared = pi squared over 9, about 1.0966, which is 1.10 to two decimal places.
  10. L = 5 · Nonzero solutions need L = n squared. 5 is not a perfect square, so sin(√5 x) does not vanish at pi and only X = 0 fits.
Worksheet · LightMySky