Linear Independence, Span and Basis · seed 1 · A4, ink-friendly. The answer key prints on its own page for grown-ups.

Reaching everywhere with nothing spare

Mathematics · Linear Algebra · ages 18-19
Name ______________________   Date ____________
  1. Mia says (1, 1) and (minus 1, minus 1) are independent because neither is the zero vector. Is Mia right?

    Circle one:   True   False

  2. What is the smallest number of vectors that can span all of R^3?

    Answer: ______________

  3. The equation c1*(1, 1) + c2*(2, 2) = (0, 0) holds with c2 = 4. What is c1?

    Answer: ______________

  4. Which of these pairs of vectors is independent in the plane?

    • (1, 2) and (2, 4)
    • (1, 0) and (0, 1)
    • (3, 6) and (1, 2)
  5. Why can the vector (5, 7) be written in only one way using (1, 0) and (0, 1)?

    • Because (1, 0) and (0, 1) are linearly independent
    • Because (5, 7) is longer than each of them
    • Because coordinates must be whole numbers
    • Because (1, 0) and (0, 1) are perpendicular to (5, 7)
  6. What is the largest possible size of an independent set in the plane?

    • 2
    • 3
    • 4
  7. What does the span of the single nonzero vector (1, 2) look like in the plane?

    • A line through the origin
    • A circle around the origin
    • The whole plane
    • A single point
  8. Why can the vector (5, 7) be written in only one way using (1, 0) and (0, 1)?

    • Because (1, 0) and (0, 1) are independent
    • Because coordinates must be whole numbers
    • Because (5, 7) is longer than each of them
  9. Write (7, 3) as a*(1, 1) + b*(1, -1). What is a?

    Answer: ______________

  10. Nadia says the set (1, 2), (2, 4), (0, 1) is a basis of the plane because it spans. What is wrong?

    • It does not span the plane
    • (2, 4) is twice (1, 2), so the set is dependent
    • Three vectors can never span the plane
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Answer key

For grown-ups. Fold this page away before handing over the rest.

Reaching everywhere with nothing spare W1-mt_5RGbip9yC9-s1

  1. False · Avoiding the zero vector is not enough: the second is minus 1 times the first.
  2. 3 · Fewer than 3 vectors span at most a plane, so 3 is the minimum, achieved by any basis.
  3. -8 · Adding components gives c1 + 2*c2 = 0, so c1 = -8 when c2 = 4.
  4. (1, 0) and (0, 1) · Only the standard basis pair is independent; each other pair holds a multiple.
  5. Because (1, 0) and (0, 1) are linearly independent · If two combinations agreed, their difference would be a nontrivial dependence, which independence forbids.
  6. 2 · Two independent vectors already span the plane, so a third one always depends on them.
  7. A line through the origin · All scalar multiples t*(1, 2) trace out the line through the origin in that direction.
  8. Because (1, 0) and (0, 1) are independent · Two writings would differ by a dependence, which independence forbids.
  9. 5 · Adding components: a + b = 7 and a - b = 3, so a = 5 and b = 2.
  10. (2, 4) is twice (1, 2), so the set is dependent · Two vectors already span the plane, so the third depends on them, and a basis needs independence.
Worksheet · LightMySky