In the pure non-competitive model, where can the inhibitor bind?
- At the active site, excluding every substrate molecule
- Away from the active site, allowing substrate to bind
- On the substrate, preventing its contact with the enzyme
At fixed enzyme and inhibitor concentrations, what does reversible competitive inhibition do to Vmax and apparent Km?
- Vmax stays constant; apparent Km increases
- Vmax increases; apparent Km stays constant
- Vmax decreases; apparent Km also decreases
Finding that an inhibitor binds away from the active site is enough to prove pure non-competitive inhibition.
Circle one: True False
An inhibitor binds only to the enzyme-substrate complex. Vmax and apparent Km both decrease by the same factor. Which inhibition type fits?
- Competitive inhibition
- Uncompetitive inhibition
- Pure non-competitive inhibition
Under otherwise identical conditions, an inhibitor leaves Vmax at 24 rate units but moves the substrate concentration giving 12 rate units from 2 to 6 mmol/L. Which model fits?
- Pure non-competitive inhibition
- Uncompetitive inhibition
- Competitive inhibition
As substrate concentration rises at fixed inhibitor concentration, why can competitive inhibition be overcome but pure non-competitive inhibition cannot?
- Substrate excludes competitive inhibitor binding, but not pure non-competitive binding
- Substrate breaks competitive inhibitor molecules apart, but stabilises pure non-competitive molecules
- Substrate dilutes competitive inhibitor concentration, but concentrates pure non-competitive inhibitor
ATP availability rises while other conditions stay suitable. What feedback response can occur in cellular respiration?
- Some regulated enzymes slow, reducing further ATP production
- Every respiration enzyme speeds up, increasing further ATP production
- All enzyme activity stops permanently, preventing further ATP production
A pathway's final product slows an earlier purified enzyme. Removing the product restores activity without replacing the enzyme. Substrate concentration, temperature and pH are unchanged. Which explanation best fits?
- The product blocks substrate binding by lowering the solution's pH
- The product irreversibly inactivates enzyme molecules until they are replaced
- The product binds reversibly, reducing activity while it remains bound