In R with its usual metric, how many limit points does A={-4,1,7} have?
Answer: ______________
Let X={a,b,c} have the discrete metric: distinct points are distance 1 apart. Which statement about {a} is true?
- It is open in X but is not closed in X.
- It is both open and closed in X.
- It is closed in X but is not open in X.
- It is neither open nor closed in X.
In R with its usual metric, what is the interior of [0,1]?
- The closed interval [0,1].
- The open interval (0,1).
- The set containing only 0 and 1.
In every metric space, arbitrary unions and finite intersections of open sets are open. An infinite intersection need not be open.
Circle one: True False
In R with its usual metric, let A=(-2,0) union (0,3). How many points lie in the interior of the closure of A but not in A?
Answer: ______________
For a map f:X->Y between metric spaces, which condition is equivalent to continuity?
- The image of every open set in X is open in Y.
- The preimage of every singleton in Y contains exactly one point of X.
- The preimage of every open set in Y is open in X.
A proof takes x in a union of open sets and tries to choose a radius that works in every member. Which change gives a valid proof?
- Use a ball from one member containing x; it also lies in the union.
- Take the minimum radius over all members, including those not containing x.
- Require x to belong to every member before choosing a ball in the union.
- Use the largest member radius, even if its ball leaves the entire union.
In any metric space, the intersection of an arbitrary family of closed sets is closed.
Circle one: True False
Let f:R->R be 0 for x<=0 and 1 for x>0. For V=(-0.5,0.5), which statement about f^-1(V) witnesses discontinuity?
- It is (0,infinity); no positive input has a ball contained in this set.
- It is all of R; both constant pieces make f continuous at 0.
- It is (-infinity,0]; no ball about 0 lies inside this set.
For f:X->Y between metric spaces, assume every open target set has an open preimage. Fix a in X and epsilon>0. Which construction proves continuity at a?
- Take a target ball B_Y(f(a),epsilon); use epsilon itself as the source radius without examining any preimage.
- Take f(B_X(a,epsilon)); call this image open and use a target ball inside it to choose the source radius.
- Take G=f^-1(B_Y(f(a),epsilon)); openness at a gives delta>0 with B_X(a,delta) inside G.
- Take G=f^-1({f(a)}); claim that this preimage must be open and contains a source ball for every epsilon.