Each of two independent observations is 0 or 4 with equal probability. The four ordered samples are equally likely. What is the expected sample mean?
Answer: ______________
A sample of three readings is 4, 6 and 8. Compute the sample mean.
Answer: ______________
For the readings 11, 13 and 15 with mean 13, the squared deviations total 8. With the n minus 1 divisor, what is the sample variance?
Priya says the expected sample mean is greater than the population mean for independent observations from the same population with finite mean. Is this claim correct?
Circle one: True False
Let Q be the sum of squared deviations from the sample mean. A sample has only one observation. Why is the sample variance Q/(n - 1) unavailable?
For five observations, dividing the sum of squared deviations from their sample mean by n gives 12. What value results when the same total is divided by n - 1?
Answer: ______________
If an estimator's bias and variance both tend to zero as the sample size grows, these conditions are sufficient for consistency.
Circle one: True False
For n >= 2 independent, identically distributed observations with finite positive variance, why does the unbiased sample variance divide by n - 1 instead of n?
For every sample size n, estimator A has bias 1 and variance 1/n; estimator B has bias 0 and variance 4/n. Both estimate the same target theta. Which statement is correct?
A class takes one sample with mean 6 and declares the population mean is exactly 6 with no uncertainty. Which statement explains the problem?