Why does zinc not qualify as a transition metal?
- Zinc sits outside the d block of the periodic table
- Its Zn2+ ion has an empty d sub-shell, like Sc3+
- Its Zn2+ ion has a full d sub-shell
What makes an element a transition metal?
- At least one stable ion with a partly filled d sub-shell
- A full d sub-shell in every one of its common ions
- Atoms that lose only their two 4s electrons in every compound
Manganese is +7 in KMnO4 and +2 in MnSO4, so it shows more than one oxidation state.
Circle one: True False
Why does scandium not qualify as a transition metal?
- Its only ion Sc3+ has an empty d sub-shell
- Scandium has no d electrons even as an uncombined atom
- Scandium forms coloured ions with several oxidation states
Why are copper(II) compounds usually coloured while zinc compounds are white?
- Copper atoms are heavier, so their compounds reflect less light
- In Cu2+ a d electron can jump to a higher, split d level
- Zinc ions have empty d orbitals, so they cannot hold ligands
Mn2+ ions catalyse the reaction between manganate(VII) and ethanedioate ions in solution. Mn2+ is oxidised to Mn3+ in the first step. What must happen next for Mn2+ to be a catalyst?
- Mn3+ is oxidised again to Mn7+ and stays there until the end
- Mn3+ is reduced back to Mn2+ by the ethanedioate ions
- Mn3+ leaves the solution as a solid, so it cannot react again
Which pair gives one heterogeneous and one homogeneous transition metal catalyst?
- Solid iron in the Haber process, and Fe2+ ions in solution
- Solid iron in the Haber process, and solid V2O5 in the Contact process
- Fe2+ ions in solution, and Fe3+ ions in the same solution
In excess ammonia, four of the six water ligands around Cu2+ are replaced by ammonia, and the colour of the solution changes. Why?
- Ammonia fills the copper d sub-shell, so no light is absorbed any more
- The new ligands split the d levels by a different amount
- Ammonia changes copper into a different element with its own colour