Decomposing a Representation from Its Character · seed 1 · A4, ink-friendly. The answer key prints on its own page for grown-ups.

Reading a group from its character table

Mathematics · Abstract Algebra · ages 23-24
Name ______________________   Date ____________
  1. Which calculation finds the multiplicity of an irreducible character in a representation character?

    • Conjugate the irreducible values, weight matched products by class size, sum and divide by |G|.
    • Multiply matching values without conjugation or class weights, sum and divide by the number of classes.
    • Conjugate the irreducible values, weight matched products by class size, sum and divide by the dimension.
  2. S3 has three conjugacy classes. A proposed character table contains only the trivial and sign rows. A student says it is complete because both rows are irreducible. Is it complete?

    Circle one:   True   False

  3. The S3 sign character is (1,-1,1) on identity, transpositions, 3-cycles. Which set is its kernel?

    • The identity and all three transpositions
    • The identity and both three-letter cycles
    • All transpositions and both three-letter cycles
    • Only the two three-letter cycles, without identity
  4. In a complex character table of a finite group, what does one row hold?

    • One group element expressed in every possible basis
    • One conjugacy class with every member written out
    • One irreducible character across all the classes
  5. The regular character of the cyclic group C3 is 3 at the identity and 0 elsewhere. What is the multiplicity of a nontrivial one-dimensional complex character?

    Answer: ______________

  6. An S3 representation has character (7,-1,1) on identity, transpositions, 3-cycles, of sizes 1,3,2. The sign row is (1,-1,1). What is its multiplicity?

    • 2
    • 1
    • 0
    • 3
  7. An S3 representation contains two trivial copies, three sign copies and one standard copy. Their dimensions are 1,1,2. What is the representation's dimension?

    Answer: ______________

  8. For a complex representation of a finite group, chi(g)=chi(e) exactly on the identity and two other elements. What do those three elements form?

    • A normal subgroup of the group
    • A conjugacy class of three elements
    • An irreducible character of degree three
  9. Dan says S3's standard character (2,0,-1) contains two trivial copies because its identity entry is 2. Class sizes are 1,3,2. Which correction fits?

    • The entry is the trivial multiplicity; no other class values are needed to justify the count.
    • That entry is dimension; the weighted trivial multiplicity is 0.
    • That entry is dimension; the weighted trivial multiplicity is 2.
  10. On S3's classes of sizes 1,3,2, a class function f has values (1,1,-1). Its squared norm is (1+3+2)/6=1. A student concludes that f must be an irreducible character.

    Circle one:   True   False

LightMySky · lightmysky.comW1-mt_ccEcWW9xAa-s1

Answer key

For grown-ups. Fold this page away before handing over the rest.

Reading a group from its character table W1-mt_ccEcWW9xAa-s1

  1. Conjugate the irreducible values, weight matched products by class size, sum and divide by |G|. · Use the normalized class-weighted inner product, conjugating the irreducible character values.
  2. False · Three conjugacy classes require three irreducible rows. The two listed rows leave one missing.
  3. The identity and both three-letter cycles · Its dimension is 1. The identity and both 3-cycles have character value 1.
  4. One irreducible character across all the classes · A row lists one irreducible character's values, with one value for each conjugacy class.
  5. 1 · The one-dimensional character has identity value 1. Only that term contributes, giving 3*1/3=1.
  6. 2 · The sign multiplicity is (7+3*(-1)*(-1)+2*1)/6=(7+3+2)/6=2.
  7. 7 · Multiply each multiplicity by its irreducible dimension: 2*1+3*1+1*2=7.
  8. A normal subgroup of the group · Equality with chi(e) identifies the representation kernel, which is a normal subgroup.
  9. That entry is dimension; the weighted trivial multiplicity is 0. · The identity entry is dimension. The trivial multiplicity is (2+0-2)/6=0.
  10. False · Norm 1 proves irreducibility only for a known representation character. Here the trivial coefficient is (1+3-2)/6=1/3, so f is not a representation character.
Worksheet · LightMySky