What intermediate forms when bromine adds to a double bond?
- An open carbocation
- A free carbon radical
- A three membered bromonium ring with shared charge
Why does the proton add to the end that gives the stabler cation?
- Stabler cations form faster and fix the regiochemistry after
- Protons always add to the more substituted carbon
- Cations never form during addition
Additions through a bromonium ion give anti addition.
Circle one: True False
Why can a bromonium intermediate never rearrange?
- Rearrangements are forbidden in all chemistry
- No open cation exists to shift, since charge stays shared in the ring
- Bromine atoms are too heavy to move
Cyclohexene is treated with bromine water. Where do the groups land?
- Bromine on the more substituted carbon, hydroxyl on the less
- Bromine on the less substituted carbon, hydroxyl on the more, trans
- Both groups on the same carbon
HBr adds to an alkene in the presence of peroxides and bromine lands on the less substituted carbon. Why?
- A bromine radical adds first through the stablest carbon radical
- The carbocation rearranged before capture
- Peroxides block all addition
A student predicts syn addition for bromine water on cyclohexene. What is the error?
- The bridge blocks one face, so opening must come from the back
- Syn addition always wins for rings
- Water never acts as a nucleophile
An addition product shows a shifted skeleton. A student blames a bromonium bridge. Why is that wrong?
- Bridges always rearrange
- Rearranged skeletons fingerprint open cations, which bridges forbid
- Skeletons never shift in any addition