What intermediate forms when bromine adds to a double bond?
- An open carbocation
- A free carbon radical waiting beside the double bond
- A three membered bromonium ring with shared charge
Why does the proton add to the end that gives the stabler cation?
- Stabler cations form faster and fix the regiochemistry after
- Protons always add to the more substituted carbon in every case
- Cations never form during addition
Additions through a bromonium ion give anti addition.
Circle one: True False
Why can a bromonium intermediate never rearrange?
- Rearrangements are forbidden in all chemistry
- No open cation exists to shift
- Bromine atoms are too heavy to move
Cyclohexene is treated with bromine water. How do the two new groups sit?
- Both new groups land on the same carbon atom
- Trans to each other across the ring
- Cis to each other on the ring
HBr adds to an alkene in the presence of peroxides and bromine lands on the less substituted carbon. Why?
- A bromine radical adds first
- The carbocation rearranged before capture
- Peroxides block all addition
A student predicts syn addition for bromine water on cyclohexene. What is the error?
- The bridge blocks one face
- Syn addition always wins for rings
- Water never acts as a nucleophile
An addition product shows a shifted skeleton. A student blames a bromonium bridge. Why is that wrong?
- Bridges always rearrange
- Rearranged skeletons fingerprint open cations
- Skeletons never shift in any addition reaction at all