On S = {u, v}, a relation contains (u, u), (v, v) and (u, v), but not (v, u). Which pair shows that symmetry fails?
- (u, u), because it relates u to itself
- (v, v), because it relates v to itself
- (u, v), because its reverse is missing
- (v, u), because it belongs to the relation
Which properties make equality on a set an equivalence relation?
- Reflexive and symmetric, without transitivity
- Symmetric and transitive, without reflexivity
- Reflexive, symmetric and transitive
How many distinct equivalence classes does congruence modulo 5 have?
Answer: ______________
What does reflexivity require of a relation?
- Every element relates to itself
- Each pair appears both ways
- Chains link through intermediates
If the classes of a and b share an element c, what follows?
- They coincide as sets
- They overlap but have different members
- One class has no elements despite containing c
On {a, b, c}, an equivalence relation consists of (a, a), (a, b), (b, a), (b, b) and (c, c). Which partition does it produce?
- {{a}, {b, c}}
- {{a, b, c}}
- {{a}, {b}, {c}}
- {{a, b}, {c}}
On {1, 2, 3}, a relation has all self-pairs and the pairs (1, 2), (2, 1), (2, 3), (3, 2). Which chain disproves transitivity?
- 1 ~ 2 and 2 ~ 1, with 1 ~ 1 present
- 1 ~ 2 and 2 ~ 3, with 1 ~ 3 absent
- 2 ~ 3 and 3 ~ 2, with 2 ~ 2 present
- 3 ~ 2 and 2 ~ 2, with 3 ~ 2 present
For integers with a related to b meaning a is less than b, which property fails?
- Transitivity: a < b < c never gives a < c
- Reflexivity: a < a never holds
- All three properties hold for this relation
Lee says the classes of 2 and 5 modulo 3 coincide, since 5 minus 2 equals 3.
Circle one: True False
A relation is reflexive and symmetric but chains do not always link through. What is it?
- An equivalence relation because two properties suffice
- An equivalence relation because symmetry implies transitivity
- Not an equivalence relation: transitivity fails