Ratio Problems
Solve problems involving the relative sizes of two quantities where missing values can be found by using integer multiplication and division facts
What a learner can do afterwards
- If the ratio of red to blue beads is 3:5 and there are 15 blue beads, find the number of red beads
- Use multiplication facts to find the missing value: 'For every 2 apples there are 5 oranges; if there are 20 oranges, how many apples?'
- Explain the multiplicative relationship between two quantities in a ratio context
1 · Read
You already know how to compare two amounts with a ratio, like 3:5. In a ratio problem, you are told one amount and asked to find the matching amount for the other side. The two amounts always scale up or down by the same multiplying number.
The ratio of red to blue beads is 3:5, and there are 15 blue beads. Blue went from 5 to 15, so it was multiplied by 3 (5 x 3 = 15). Red and blue always scale together, so multiply red by 3 too: 3 x 3 = 9. There are 9 red beads.
Find the multiplying number first. Divide the new amount by its matching ratio number, then multiply the other ratio number by that same amount.
To solve a ratio problem, work out how much one side was scaled, then scale the other side by the same amount.
More to read
Ratio review
A ratio compares two amounts with a colon, like 3:5 for red to blue beads. It does not say there are exactly 3 and 5 beads; it says every 3 reds come with 5 blues. Double the batch and 6:10 means exactly the same mix, because both sides grew by the same multiplier. To find a missing value, find what one part is worth. With 15 blue beads in a 3:5 mix, each part is 15 divided by 5 = 3 beads, so red is 3 parts of 3 = 9 beads. The multiplier (here 3) works on both sides at once, which keeps the mix unchanged.
Ratio tables
Ratio tables lay out equivalent ratios row by row so the pattern shows. For 2 apples to 5 oranges, the table reads 2:5, 4:10, 6:15, 8:20. Each step adds one more copy of the base ratio, and the multiplier column (1, 2, 3, 4) tells you how far you scaled. Tables also catch additive traps. Someone who adds 2 to each side of 2:5 gets 4:7, which breaks the table pattern and tastes wrong in a recipe. Only multiplying both sides preserves the ratio, and the table proves it at a glance.
Introduction to ratios
Ratios describe real situations: juice concentrate to water, flour to sugar, wins to matches. The order matters: 3:5 for red:blue is different from 5:3. Always label which number belongs to which thing before calculating, or the answer describes the wrong mix. Scaling a ratio answers how much questions. Twenty oranges at 2 apples per 5 oranges means 4 groups of the base pair, so 4 times 2 = 8 apples. Division finds the group count, multiplication finds the missing amount: that pair solves almost every ratio problem.
6.1: Ratio and Proportion
A proportion is an equation of two equal ratios, such as 3/5 = 9/15. Cross products test equality fast: 3 times 15 = 45 and 5 times 9 = 45, so the ratios match. Unequal cross products expose a broken ratio immediately. Proportions also solve for unknowns: setting 3/5 = r/15 and cross multiplying gives 5r = 45, so r = 9. The unit rate view agrees: 3 reds per 5 blues is 0.6 reds per blue, and 0.6 times 15 is 9.
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