LightMySky
به انگلیسی

The Imaginary Unit and Complex Arithmetic

Quadratics with no real roots stop being dead ends: i is defined so that i squared is -1, and numbers of the form a + bi add, multiply, conjugate and divide by the ordinary rules of algebra.

No account needed. Progress saves in this browser.

What a learner can do afterwards

  • Solve a quadratic with negative discriminant and write both roots in a + bi form
  • Add, multiply and divide two complex numbers, using the conjugate for division
  • Explain why the rules of real algebra carry over once i squared is replaced by -1
  • Plot a + bi as the point (a, b) and find its distance from the origin with Pythagoras

1 · Read

Some quadratics have no real roots, and i rescues them so every quadratic has an answer. Define i by i squared equals minus one. Then x squared plus 4 equals zero gives x squared equals minus 4, so x is 2i or minus 2i. Each answer fits a plus bi form, with real and imaginary parts.

Try it together

Combine real and imaginary parts separately: (3 + 2i) plus (1 + 4i) is 4 + 6i, and (2 + 3i) minus (5 + i) is minus 3 + 2i. To multiply, expand term by term and swap i squared for minus one. A conjugate pair (flip the i sign) gives a real answer: (3 + i) times (3 - i) is 9 + 1, which is 10.

Divide by multiplying top and bottom with the bottom's conjugate. Then (1 + i) over (1 - i) becomes 2i over 2, which is i. Powers cycle too: i to the 4th is i squared times i squared, or minus one times minus one, which is 1. The roots 2i and minus 2i multiply to 4.

Treat complex numbers with ordinary algebra, then swap every i squared for minus one at the end. Expand brackets fully: (1 + i) squared gives 1 + 2i + i squared, which is 2i. Dropping the middle term or leaving i squared in the answer are the two classic slips.

Try it together

Plot a plus bi as the point (a, b): across for the real part, up for the imaginary part. Its distance from the origin uses Pythagoras, since the gaps a and b are legs of a right triangle. For 6 + 8i the point is (6, 8). Square each gap: 36 and 64. Add: 36 + 64 = 100. The root of 100 is 10, so 6 + 8i sits 10 from the origin.

point (6, 8) is 6 + 8iacross 6, up 836 + 64 = 100root 100 is 10

With i squared as minus one, complex numbers add, multiply, and divide by the ordinary rules of algebra.

Readings 'Why i exists', 'Multiplying and the conjugate', 'Dividing with the conjugate' and 'Powers of i and the complex plane' are original to this dataset. All 8 extra questions are original to this dataset.

2 · Watch

به انگلیسی

Take it off screen

Print a worksheetA4 with an answer key page for grown-ups. No screen, no internet.

Where it sits

Where this leads

Jobs that lean on this skill. Follow one to see everything it is built on.

Then practise

16 questions wait behind this lesson, each with its answer explained. Every answer feeds the sky: stars light as they are learned, and dim when it is time to come back.

Spotted a problem on this page? Tell us
The Imaginary Unit and Complex Arithmetic · Mathematics, ages 17 to 18 · LightMySky