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The Imaginary Unit and Complex Arithmetic

Quadratics with no real roots stop being dead ends: i is defined so that i squared is -1, and numbers of the form a + bi add, multiply, conjugate and divide by the ordinary rules of algebra.

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What a learner can do afterwards

  • Solve a quadratic with negative discriminant and write both roots in a + bi form
  • Add, multiply and divide two complex numbers, using the conjugate for division
  • Explain why the rules of real algebra carry over once i squared is replaced by -1
  • Plot a + bi as the point (a, b) and find its distance from the origin with Pythagoras

1 · Read

Some quadratics have no real roots, and i rescues them so every quadratic has an answer. Define i by i squared equals minus one. Then x squared plus 4 equals zero gives x squared equals minus 4, so x is 2i or minus 2i. Each answer fits a plus bi form, with real and imaginary parts.

Try it together

Add parts with parts: (3 + 2i) plus (1 + 4i) joins 3 with 1 and 2i with 4i, giving 4 + 6i. Subtraction matches: (2 + 3i) minus (5 + i) is minus 3 + 2i. For products, use a conjugate (flip the i sign). So (3 + i) times (3 - i) expands to 9 + 1, which is 10, since i squared is minus one.

Divide by multiplying top and bottom with the bottom's conjugate. Then (1 + i) over (1 - i) becomes 2i over 2, which is i. Powers cycle too: i to the 4th is i squared times i squared, or minus one times minus one, which is 1. The roots 2i and minus 2i multiply to 4.

Treat complex numbers with ordinary algebra, then swap every i squared for minus one at the end. Expand brackets fully: (1 + i) squared gives 1 + 2i + i squared, which is 2i. Dropping the middle term or leaving i squared in the answer are the two classic slips.

Try it together

Plot a plus bi as the point (a, b): across for the real part, up for the imaginary part. Its distance from the origin uses Pythagoras, since the gaps a and b are legs of a right triangle. For 6 + 8i the point is (6, 8). Square each gap: 36 and 64. Add: 36 + 64 = 100. The root of 100 is 10, so 6 + 8i sits 10 from the origin.

point (6, 8) is 6 + 8iacross 6, up 836 + 64 = 100root 100 is 10

With i squared as minus one, complex numbers add, multiply, and divide by the ordinary rules of algebra.

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The Imaginary Unit and Complex Arithmetic · Mathematics, ages 17 to 18 · LightMySky